How many grams of baking powder must be used to generate .750 L of CO2?

If .750 L of CO2 is needed for a cake and each kilogram of baking powder contains 168 grams of NaHCO3, how many grams of baking powder must be used to generate this amount of CO2? The density of CO2 at baking temperature is about 1.20 g/l.





the balance equation is- 2NaHCO2+Ca(H2PO4)--%26gt; Na2HP04+CaHPO4+2CO2+2H20How many grams of baking powder must be used to generate .750 L of CO2?
hints





calculate mass CO2 needed


convert to moles CO2 needed


convert to moles NaHCO3 needed


convert to mass NaHCO3 needed


convert to mass of baking soda








solution....





.750 L CO2 x 1.20 g / L = 0.90 g CO2





moles CO2 = mass / mw = 0.90 g CO2 / 44.0 g/mole = 0.0205 moles CO2





from balanced equation, 2 CO2 requires 2 NaHCO3





0.0205 moles CO2 x (2 NaHCO3 / 2 CO2) = .0205 moles NaHCO3





moles NaHCO3 = wt / mw ----%26gt; wt NaHCO3= moles x mw = 0.0205 moles x 84.00 g/mole = 1.72 g NaHCO3





finally convert to baking soda....





1.72 g NaHCO3 x (1 kg baking soda / 168 g NaHCO3) x (1000 g / kg) = 10.2 grams baking soda